Classic ASP

Check if a MIME Part is an Image

Demonstrates the Chilkat Mime.IsImage method, which returns whether the Content-Type begins with image/. It takes no arguments and applies to the current part.

Note: The file path is relative to the application's current working directory. Absolute paths may also be used. Supply the path to your own file.

Background: This locates image parts — inline graphics in a multipart/related message, or image attachments — so your code can preview thumbnails, extract them, or handle them differently from documents. It matches any image/ subtype, including image/svg+xml.

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Classic ASP

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<%
success = 0

'  Demonstrates the Mime.IsImage method, which returns whether the Content-Type begins with image/.  It takes no arguments and applies to the current
'  part.  This example iterates the parts of a multipart message and reports which ones match.

set mime = Server.CreateObject("Chilkat.Mime")
success = mime.LoadMimeFile("qa_data/multipart_message.eml")
If (success = 0) Then
    Response.Write "<pre>" & Server.HTMLEncode( mime.LastErrorText) & "</pre>"
    Response.End
End If

n = mime.NumParts
set part = Server.CreateObject("Chilkat.Mime")

For i = 0 To n - 1
    success = mime.PartAt(i,part)
    If (success = 0) Then
        Response.Write "<pre>" & Server.HTMLEncode( mime.LastErrorText) & "</pre>"
        Response.End
    End If

    If (part.IsImage()) Then
        Response.Write "<pre>" & Server.HTMLEncode( "Part " & i & " (" & part.ContentType & ") is an image.") & "</pre>"
    End If

Next

%>
</body>
</html>