Java
Java
Iterate over Direct Child Nodes by Index
See more XML Examples
Demonstrates some ways to iterate over direct child nodes by index.The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:
<root>
<fruit color="red">apple</fruit>
<fruit color="green">pear</fruit>
<veg color="orange">carrot</veg>
<meat animal="cow">beef</meat>
<xyz>
<fruit color="blue">blueberry</fruit>
<veg color="green">broccoli</veg>
</xyz>
<fruit color="purple">grape</fruit>
<cheese color="yellow">cheddar</cheese>
</root>
Chilkat Java Downloads
import com.chilkatsoft.*;
public class ChilkatExample {
static {
try {
System.loadLibrary("chilkat");
} catch (UnsatisfiedLinkError e) {
System.err.println("Native code library failed to load.\n" + e);
System.exit(1);
}
}
public static void main(String argv[])
{
boolean success = false;
CkXml xml = new CkXml();
CkXml child;
// The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
success = xml.LoadXmlFile("get_child.xml");
if (success != true) {
System.out.println(xml.lastErrorText());
return;
}
// The NumChildren property contains the number of direct
// child nodes. Note: The child nodes under "xyz" are NOT
// direct children of "root". Therefore, the "root" node has
// 7 direct children
System.out.println("NumChildren = " + xml.get_NumChildren());
// Iterate over the direct children by index. The first child
// is at index 0.
int i;
for (i = 0; i <= xml.get_NumChildren() - 1; i++) {
// access the tag and content directly by index:
System.out.println(i + ": " + xml.getChildTagByIndex(i) + " : " + xml.getChildContentByIndex(i));
}
System.out.println("-----");
// Do the same as the above loop, but get the child node
// and access the Tag and Content properties:
for (i = 0; i <= xml.get_NumChildren() - 1; i++) {
child = xml.GetChild(i);
System.out.println(i + ": " + child.tag() + " : " + child.content());
}
System.out.println("-----");
// Do the same as the above loop, but instead of creating
// a new object instance for each child, call GetChild2 to
// update the object's reference instead.
for (i = 0; i <= xml.get_NumChildren() - 1; i++) {
// Navigate to the Nth child.
success = xml.GetChild2(i);
System.out.println(i + ": " + xml.tag() + " : " + xml.content());
// Navigate back up to the parent:
success = xml.GetParent2();
}
System.out.println("-----");
// Notice that the Content of the "xyz" node is empty. This is correct.
// The "xyz" node has no Content, but 2 direct children
}
}