Sample code for 30+ languages & platforms
Java

Iterate JSON where Member Names are Data Values

See more JSON Examples

Demonstrates how to parse JSON where member names are not keywords, but instead are data values.

Chilkat Java Downloads

Java
import com.chilkatsoft.*;

public class ChilkatExample {

  static {
    try {
        System.loadLibrary("chilkat");
    } catch (UnsatisfiedLinkError e) {
      System.err.println("Native code library failed to load.\n" + e);
      System.exit(1);
    }
  }

  public static void main(String argv[])
  {
    boolean success = false;

    CkJsonObject json = new CkJsonObject();

    success = json.LoadFile("qa_data/json/valuesAsNames.json");

    // Imagine we have JSON such as the following:

    // {
    //   "1680": {
    //     "entity_id": "1680",
    //     "type_id": "simple",
    //     "sku": "123"
    //   },
    //   "1701": {
    //     "entity_id": "1701",
    //     "type_id": "simple",
    //     "sku": "456"
    //   }
    // }
    // 

    // This presents a parsing problem because the member names, such as "1680"
    // are not keywords.  Instead they are data values.  We don't know what they
    // may be in advance.  

    // To solve, we iterate over the members, get the name of each, ...
    int numMembers = json.get_Size();
    int i;
    for (i = 0; i <= numMembers - 1; i++) {

        String name = json.nameAt(i);

        System.out.println(name + ":");
        CkJsonObject jRecord = json.ObjectAt(i);

        System.out.println("entity_id: " + jRecord.stringOf("entity_id"));
        System.out.println("type_id: " + jRecord.stringOf("type_id"));
        System.out.println("sku: " + jRecord.stringOf("sku"));

        }
  }
}