Classic ASP
SOAP sendBill Call to sunat.gob.pe

Demonstrates how to make a SOAP call to sunat.gob.pe for the sendBill method.
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Classic ASP
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<%
success = 0

' This example requires the Chilkat API to have been previously unlocked.
' See Global Unlock Sample for sample code.

' --------------------------------------------------------------------------------
' Also see Chilkat's Online WSDL Code Generator
' to generate code and SOAP Request and Response XML for each operation in a WSDL.
' --------------------------------------------------------------------------------

set http = Server.CreateObject("Chilkat.Http")

' The SOAP XML will look like this:
' <?xml version="1.0" encoding="utf-8"?>
' <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ser="http://service.sunat.gob.pe">
'     <soapenv:Header/>
'     
'     <soapenv:Body>
'         <ser:sendBill>
'             <fileName>20601523999-03-B001-00000002.zip</fileName>
'             <contentFile>UEsDBBQ ... AAAAA==</contentFile>
'         </ser:sendBill>
'     </soapenv:Body>
' </soapenv:Envelope>

' Build the above SOAP XML.
set xml = Server.CreateObject("Chilkat.Xml")
xml.Tag = "soapenv:Envelope"
success = xml.AddAttribute("xmlns:soapenv","http://schemas.xmlsoap.org/soap/envelope/")
success = xml.AddAttribute("xmlns:ser","http://service.sunat.gob.pe")
xml.UpdateChildContent "soapenv:Header",""
xml.UpdateChildContent "soapenv:Body|ser:sendBill|fileName","20601523999-03-B001-00000002.zip"
xml.UpdateChildContent "soapenv:Body|ser:sendBill|contentFile","UEsDBBQ ... AAAAA=="

' Alternatively, load the XML from a file.  (Remove this line if you wish to build the XML as shown above.)
success = xml.LoadXmlFile("qa_data/soap/envio_sunat_peru.xml")

strXml = xml.GetXml()

http.SetRequestHeader "SOAPAction","urn:sendBill"

endPoint = "https://e-beta.sunat.gob.pe/ol-ti-itcpfegem-beta/billService"

set resp = Server.CreateObject("Chilkat.HttpResponse")
success = http.HttpStr("POST",endPoint,strXml,"utf-8","text/xml",resp)
If (success = 0) Then
    Response.Write "<pre>" & Server.HTMLEncode( http.LastErrorText) & "</pre>"
    Response.End
End If

responseStatusCode = resp.StatusCode

' You may wish to verify that the responseStatusCode equals 200...
Response.Write "<pre>" & Server.HTMLEncode( "Response Status Code: " & responseStatusCode) & "</pre>"

' You may examine the exact HTTP header sent with the POST like this:
Response.Write "<pre>" & Server.HTMLEncode( "LastHeader:") & "</pre>"
Response.Write "<pre>" & Server.HTMLEncode( http.LastHeader) & "</pre>"

' Examine the XML returned by the web service:
Response.Write "<pre>" & Server.HTMLEncode( "XML Response:") & "</pre>"
set xmlResp = Server.CreateObject("Chilkat.Xml")
success = xmlResp.LoadXml(resp.BodyStr)
Response.Write "<pre>" & Server.HTMLEncode( xmlResp.GetXml()) & "</pre>"

' Use this online tool to generate parsing code from response XML: 
' Generate Parsing Code from XML

%>
</body>
</html>