Classic ASP
HTTP multipart/form-data Upload

Demonstrates how to upload files to an HTTP server using a multipart/form-data POST.
Chilkat Classic ASP Downloads

Classic ASP
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<%
success = 0

' This example requires the Chilkat API to have been previously unlocked.
' See Global Unlock Sample for sample code.

set http = Server.CreateObject("Chilkat.Http")

set req = Server.CreateObject("Chilkat.HttpRequest")
req.HttpVerb = "POST"
req.ContentType = "multipart/form-data"
req.Path = "rcvFormDataUpload.aspx"

' Send an "Expect: 100-continue" header in the request.
' This causes the HTTP server to end a 100-continue response
' immediately after receiving the HTTP header.  The client
' (Chilkat) will receive this intermediate response, and if
' it's not an error response, it knows that the HTTP server will
' accept the data that is forthcoming.
' The alternative is to get an error response after trying to upload
' the entire contents of the files.
req.AddHeader "Expect","100-continue"

' Call AddFileForUpload2 for each file to be uploaded in the HTTP multipart/form-data POST
' To allow Chilkat to determine the content-type automatically based on file-extension,
' call AddFileForUpload instead.

' The 1st arg is the filename passed in the HTTP request.
' The 2nd arg is the path in the local filesytem.
' The file is not loaded into memory.  It is streamed directly from the file
' when the HTTP POST is sent.
success = req.AddFileForUpload2("starfish.jpg","c:/qa_data/starfish.jpg","image/jpg")
If (success = 0) Then
    Response.Write "<pre>" & Server.HTMLEncode( req.LastErrorText) & "</pre>"
    Response.End
End If

success = req.AddFileForUpload("something.pdf","c:/qa_data/something.pdf")
If (success = 0) Then
    Response.Write "<pre>" & Server.HTMLEncode( req.LastErrorText) & "</pre>"
    Response.End
End If

' Its also possible to add a file from a string:
success = req.AddStringForUpload("test.xml","test.xml","<abc>This is the test.xml content</abc>","utf-8")
' We'll assume success since no files are involved..

' This sends the HTTP request (with 3 files being uploaded) to
' http://www.mywebserver123abc.com/rcvFormDataUpload.aspx
set resp = Server.CreateObject("Chilkat.HttpResponse")
success = http.HttpSReq("www.mywebserver123abc.com",80,0,req,resp)
If (success = 0) Then
    Response.Write "<pre>" & Server.HTMLEncode( http.LastErrorText) & "</pre>"
    Response.End
End If

Response.Write "<pre>" & Server.HTMLEncode( "HTTP response status: " & resp.StatusCode) & "</pre>"
' See the online reference documentation for 
' other information that can be obtained from the response object.

' To send using SSL/TLS, do this instead.
' This sends to https://www.mywebserver123abc.com/rcvFormDataUpload.aspx
success = http.HttpSReq("www.mywebserver123abc.com",443,1,req,resp)
If (success = 0) Then
    Response.Write "<pre>" & Server.HTMLEncode( http.LastErrorText) & "</pre>"
    Response.End
End If

Response.Write "<pre>" & Server.HTMLEncode( "HTTP response status: " & resp.StatusCode) & "</pre>"
' See the online reference documentation for 
' other information that can be obtained from the response object.

%>
</body>
</html>