(C++) Iterate over Direct Children with a Specific Tag

Demonstrates how to iterate over direct children having a specific tag.

The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Downloads:

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MAC OS X C/C++ Libraries

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HP-UX C++ Libraries

BlackBerry QNX C++ Libraries

#include <CkXml.h>

void ChilkatSample(void)
    {
    CkXml xml;
    CkXml *child = 0;
    long numWithTag;
    long i;

    bool success;
    //  The sample input XML is available at http://www.chilkatsoft.com/data/fruit.xml
    success = xml.LoadXmlFile("fruit.xml");
    if (success != true) {
        printf("%s\n",xml.lastErrorText());
        return;
    }

    //   Get the number of direct children having the tag "fruit"
    numWithTag = xml.NumChildrenHavingTag("fruit");

    if (numWithTag > 0) {

        for (i = 0; i <= numWithTag - 1; i++) {
            child = xml.GetNthChildWithTag("fruit",i);
            printf("%d: %s : %s\n",i,child->tag()
                ,child->content());
            delete child;
        }

        printf("-----\n");

        //  Do the same as the above loop, but instead of creating
        //  a new object instance for each child, call GetNthChildWithTag2 to
        //  update the object's reference instead.
        for (i = 0; i <= numWithTag - 1; i++) {
            //  Navigate to the Nth child.
            xml.GetNthChildWithTag2("fruit",i);
            printf("%d: %s : %s\n",i,xml.tag()
                ,xml.content());
            //  Navigate back up to the parent:
            xml.GetParent2();
        }

        printf("-----\n");

    }


    }