(C++) Iterate over Direct Child Nodes by Index

Demonstrates some ways to iterate over direct child nodes by index.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Downloads:

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#include <CkXml.h>

void ChilkatSample(void)
    {
    CkXml xml;
    CkXml *child = 0;

    bool success;
    //  The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
    success = xml.LoadXmlFile("get_child.xml");
    if (success != true) {
        printf("%s\n",xml.lastErrorText());
        return;
    }

    //  The NumChildren property contains the number of direct
    //  child nodes.  Note: The child nodes under "xyz" are NOT
    //  direct children of "root".  Therefore, the "root" node has
    //  7 direct children
    printf("NumChildren = %d\n",xml.get_NumChildren());

    //  Iterate over the direct children by index. The first child
    //  is at index 0.
    long i;
    for (i = 0; i <= xml.get_NumChildren() - 1; i++) {
        //   access the tag and content directly by index:
        printf("%d: %s : %s\n",i,xml.getChildTagByIndex(i)
            ,xml.getChildContentByIndex(i));

    }

    printf("-----\n");

    //  Do the same as the above loop, but get the child node
    //  and access the Tag and Content properties:
    for (i = 0; i <= xml.get_NumChildren() - 1; i++) {
        child = xml.GetChild(i);
        printf("%d: %s : %s\n",i,child->tag()
            ,child->content());
        delete child;
    }

    printf("-----\n");

    //  Do the same as the above loop, but instead of creating
    //  a new object instance for each child, call GetChild2 to
    //  update the object's reference instead.
    for (i = 0; i <= xml.get_NumChildren() - 1; i++) {
        //  Navigate to the Nth child.
        xml.GetChild2(i);
        printf("%d: %s : %s\n",i,xml.tag()
            ,xml.content());
        //  Navigate back up to the parent:
        xml.GetParent2();
    }

    printf("-----\n");

    //  Notice that the Content of the "xyz" node is empty.  This is correct.
    //  The "xyz" node has no Content, but 2 direct children.

    }