(VB.NET) Send XMLHttpRequest and Get Response

Demonstrates how to send an HTTP XML request and retrieve the response.

Download: Chilkat .NET Assemblies

Dim http As New Chilkat.Http()

Dim success As Boolean

'  Any string unlocks the component for the 1st 30-days.
success = http.UnlockComponent("Anything for 30-day trial")
If (success <> true) Then
    TextBox1.Text = TextBox1.Text & http.LastErrorText & vbCrLf
    Exit Sub
End If


'  The XML sent in the body of the request is application
'  specified -- it should contain whatever the server-side
'  application is expecting..
Dim xmlStr As String
xmlStr = "<?xml version=""1.0"" encoding=""UTF-8""?><appXml><something>123</something></appXml>"

'  The PostXml method may be called to send the XMLHttpRequest
'  using the "POST" HTTP method (also known as "verb").
Dim urlEndpoint As String
urlEndpoint = "http://www.chilkatsoft.com/xmlEcho.asp"
Dim xmlCharset As String
xmlCharset = "utf-8"

Dim response As Chilkat.HttpResponse
response = http.PostXml(urlEndpoint,xmlStr,xmlCharset)
If (response Is Nothing ) Then
    TextBox1.Text = TextBox1.Text & http.LastErrorText & vbCrLf
    Exit Sub
End If


'  The raw HTTP request sent by the above call is:
'  
POST /xmlEcho.asp HTTP/1.1
Content-Type: text/xml
User-Agent: Chilkat/1.0.0 (+http://www.chilkatsoft.com/ChilkatHttpUA.asp)
Host: www.chilkatsoft.com
Accept: */*
Accept-Charset: ISO-8859-1,utf-8;q=0.7,*; q=0.7
Accept-Language: en-us,en;q=0.5
Accept-Encoding: gzip
Content-Length: 81

<?xml version="1.0" encoding="UTF-8"?><appXml><something>123</something></appXml>


'  Examine the Body of the HTTP response
'  This would be the XML response sent by the server.
TextBox1.Text = TextBox1.Text & response.BodyStr & vbCrLf