Simple HTTP POST

Demonstrates a simple HTTP POST.

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Dim req As New Chilkat.HttpRequest()
Dim http As New Chilkat.Http()

Dim success As Boolean

'  Any string unlocks the component for the 1st 30-days.
success = http.UnlockComponent("Anything for 30-day trial")
If (success <> true) Then
    MsgBox(http.LastErrorText)
    Exit Sub
End If


'  This example simulates this FORM:
'  <form action="processPost.asp" method="post">
'  First name: <input type="text" name="firstName"><br />
'  Last name: <input type="text" name="lastName"><br />
'  <input type="submit" value="Submit">
'  </form>
'  The online FORM is found at this URL:
'  http://www.chilkatsoft.com/simpleForm.html

'  Build an HTTP POST Request:
req.UsePost()

'  The FORM target is http://www.chilkatsoft.com/processPost.asp
'  An easy way of filling out most of the HTTP request object
'  is to call SetFromUrl:
req.SetFromUrl("http://www.chilkatsoft.com/processPost.asp")

'  The only remaining task is to add the params to the
'  HTTP request object:
req.AddParam("firstName","Matt")
req.AddParam("lastName","Jones")

'  Send the HTTP POST and get the response.
'  The POST is being sent to chilkatsoft.com, on port 80
'  (the default HTTP port), and not using SSL.
Dim domain As String
Dim port As Long
Dim ssl As Boolean
domain = "chilkatsoft.com"
port = 80
ssl = false

'  The HTTP POST is sent here:
Dim resp As Chilkat.HttpResponse
resp = http.SynchronousRequest(domain,port,ssl,req)
If (resp Is Nothing ) Then
    TextBox1.Text = TextBox1.Text & http.LastErrorText & vbCrLf
Else
    '  Display the HTML source of the page returned.
    TextBox1.Text = TextBox1.Text & resp.BodyStr & vbCrLf

End If