Visual Basic Examples

ChilkatHOMEAndroid™ASPVisual BasicVB.NETC#iOS (IPhone)Objective-CC++CMFCDelphiFoxProJavaPerl
PHP ExtensionPHP ActiveXPythonPowerShellRubySQL ServerVBScript

VB Examples

Bounced Mail
Bz2
Character Encoding
CSV
Digital Certificates
Digital Signatures
Email
FTP
HTML Conversion
HTTP
IMAP
Encryption
MHT / HTML Email
POP3
RSA
S/MIME
SFTP
SMTP
Socket
Spider
SSH
SSH Key
SSH Tunnel
String
Tar
Upload
XML
XMP
Zip Compression

More Examples...
Amazon S3
Email Object
DKIM / DomainKey
NTLM
DH Key Exchange
DSA
FileAccess
RSS
Atom
Self-Extractor
Service
Bzip2
PPMD
Deflate
LZW


VB Strings
VB Byte Array

 

 

 

 

 

 

 

(Visual Basic) Iterate over Direct Child Nodes by Index

Demonstrates some ways to iterate over direct child nodes by index.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Download Chilkat XML ActiveX

Dim xml As New ChilkatXml
Dim child As ChilkatXml

Dim success As Long
'  The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
success = xml.LoadXmlFile("get_child.xml")
If (success <> 1) Then
    Text1.Text = Text1.Text & xml.LastErrorText & vbCrLf
    Exit Sub
End If

'  The NumChildren property contains the number of direct
'  child nodes.  Note: The child nodes under "xyz" are NOT
'  direct children of "root".  Therefore, the "root" node has
'  7 direct children
Text1.Text = Text1.Text & "NumChildren = " & xml.NumChildren & vbCrLf

'  Iterate over the direct children by index. The first child
'  is at index 0.
Dim i As Long
For i = 0 To xml.NumChildren - 1
    '   access the tag and content directly by index:
    Text1.Text = Text1.Text & i & ": " & xml.GetChildTagByIndex(i) _
         & " : " & xml.GetChildContentByIndex(i) & vbCrLf

Next
Text1.Text = Text1.Text & "-----" & vbCrLf

'  Do the same as the above loop, but get the child node
'  and access the Tag and Content properties:
For i = 0 To xml.NumChildren - 1
    Set child = xml.GetChild(i)
    Text1.Text = Text1.Text & i & ": " & child.Tag _
         & " : " & child.Content & vbCrLf

Next
Text1.Text = Text1.Text & "-----" & vbCrLf

'  Do the same as the above loop, but instead of creating
'  a new object instance for each child, call GetChild2 to
'  update the object's reference instead.
For i = 0 To xml.NumChildren - 1
    '  Navigate to the Nth child.
    xml.GetChild2 i
    Text1.Text = Text1.Text & i & ": " & xml.Tag _
         & " : " & xml.Content & vbCrLf
    '  Navigate back up to the parent:
    xml.GetParent2 
Next
Text1.Text = Text1.Text & "-----" & vbCrLf

'  Notice that the Content of the "xyz" node is empty.  This is correct.
'  The "xyz" node has no Content, but 2 direct children.

© 2000-2012 Chilkat Software, Inc. All Rights Reserved.