Simple HTTP POST

Demonstrates a simple HTTP POST.

Download Chilkat HTTP ActiveX

Dim req As New ChilkatHttpRequest
Dim http As New ChilkatHttp

Dim success As Long

'  Any string unlocks the component for the 1st 30-days.
success = http.UnlockComponent("Anything for 30-day trial")
If (success <> 1) Then
    MsgBox http.LastErrorText
    Exit Sub
End If

'  This example simulates this FORM:
'  <form action="processPost.asp" method="post">
'  First name: <input type="text" name="firstName"><br />
'  Last name: <input type="text" name="lastName"><br />
'  <input type="submit" value="Submit">
'  </form>
'  The online FORM is found at this URL:
'  http://www.chilkatsoft.com/simpleForm.html

'  Build an HTTP POST Request:
req.UsePost 

'  The FORM target is http://www.chilkatsoft.com/processPost.asp
'  An easy way of filling out most of the HTTP request object
'  is to call SetFromUrl:
req.SetFromUrl "http://www.chilkatsoft.com/processPost.asp"

'  The only remaining task is to add the params to the
'  HTTP request object:
req.AddParam "firstName","Matt"
req.AddParam "lastName","Jones"

'  Send the HTTP POST and get the response.
'  The POST is being sent to chilkatsoft.com, on port 80
'  (the default HTTP port), and not using SSL.
Dim domain As String
Dim port As Long
Dim ssl As Long
domain = "chilkatsoft.com"
port = 80
ssl = 0

'  The HTTP POST is sent here:
Dim resp As ChilkatHttpResponse
Set resp = http.SynchronousRequest(domain,port,ssl,req)
If (resp Is Nothing ) Then
    Text1.Text = Text1.Text & http.LastErrorText & vbCrLf
Else
    '  Display the HTML source of the page returned.
    Text1.Text = Text1.Text & resp.BodyStr & vbCrLf

End If