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PBKDF2 - Derive Key from PasswordDemonstrates how to derive a symmetric encryption key from a password using PBKDF2. This example matches the results found at this URL: http://www.di-mgt.com.au/cryptoKDFs.html#examplespbkdf
Dim crypt As New ChilkatCrypt2 Dim success As Long success = crypt.UnlockComponent("Anything for 30-day trial") If (success <> 1) Then MsgBox crypt.LastErrorText Exit Sub End If Dim hexKey As String ' http://www.di-mgt.com.au/cryptoKDFs.html#examplespbkdf Dim pw As String pw = "password" Dim pwCharset As String pwCharset = "ansi" ' Hash algorithms may be: sha1, md2, md5, etc. Dim hashAlg As String hashAlg = "sha1" ' The salt should be 8 bytes: Dim saltHex As String saltHex = "78578E5A5D63CB06" Dim iterationCount As Long iterationCount = 2048 ' Derive a 192-bit key from the password. Dim outputBitLen As Long outputBitLen = 192 ' The derived key is returned as a hex or base64 encoded string. ' (Note: The salt argument must be a string that also uses ' the same encoding.) Dim enc As String enc = "hex" hexKey = crypt.Pbkdf2(pw,pwCharset,hashAlg,saltHex,iterationCount,outputBitLen,enc) Text1.Text = Text1.Text & hexKey & vbCrLf ' The output should have this value: ' BFDE6BE94DF7E11DD409BCE20A0255EC327CB936FFE93643 |
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