(Ruby) Iterate over Direct Child Nodes by Index

Demonstrates some ways to iterate over direct child nodes by index.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Downloads for Windows/Linux and Install Instructions

require 'chilkat'

xml = Chilkat::CkXml.new()

#  The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
success = xml.LoadXmlFile("get_child.xml")
if (success != true)
    print xml.lastErrorText() + "\n";
    exit
end

#  The NumChildren property contains the number of direct
#  child nodes.  Note: The child nodes under "xyz" are NOT
#  direct children of "root".  Therefore, the "root" node has
#  7 direct children
print "NumChildren = " + xml.get_NumChildren().to_s().to_s() + "\n";

#  Iterate over the direct children by index. The first child
#  is at index 0.

for i in 0 .. xml.get_NumChildren() - 1
    #   access the tag and content directly by index:
    print i.to_s() + ": " + xml.getChildTagByIndex(i) + 
        " : " + xml.getChildContentByIndex(i) + "\n";

end
print "-----" + "\n";

#  Do the same as the above loop, but get the child node
#  and access the Tag and Content properties:
for i in 0 .. xml.get_NumChildren() - 1
    # child is a CkXml
    child = xml.GetChild(i)
    print i.to_s() + ": " + child.tag() + 
        " : " + child.content() + "\n";

end
print "-----" + "\n";

#  Do the same as the above loop, but instead of creating
#  a new object instance for each child, call GetChild2 to
#  update the object's reference instead.
for i in 0 .. xml.get_NumChildren() - 1
    #  Navigate to the Nth child.
    xml.GetChild2(i)
    print i.to_s() + ": " + xml.tag() + 
        " : " + xml.content() + "\n";
    #  Navigate back up to the parent:
    xml.GetParent2()
end
print "-----" + "\n";

#  Notice that the Content of the "xyz" node is empty.  This is correct.
#  The "xyz" node has no Content, but 2 direct children.