Chilkat HOME ASP Visual Basic VB.NET C# Visual C++ C MFC Delphi FoxPro Java Perl PHP Python Ruby SQL Server VBScript
|
Upload Files to Web ServerDemonstrates how to upload files from an application to a web server. Note: There must be something provided on the server-side to consume the upload. It could be an ASP or ASP.NET script, Perl, C++ CGI, PHP, Ruby, etc,. However, uploading via HTTP is not the same as uploading via FTP where the FTP server handles receiving the file and saving to disk. The C# code behind http://www.chilkatsoft.com/receiveUpload.aspx may be found at this URL: C# to Receive Upload in ASP.NET. require 'chilkat' http = Chilkat::CkHttp.new() # Any string unlocks the component for the 1st 30-days. success = http.UnlockComponent("Anything for 30-day trial") if (success != true) print http.lastErrorText() + "\n" exit end # Build a HTTP request with the files to be uploaded: req = Chilkat::CkHttpRequest.new() req.UseUpload() # The URL we'll be posting to is: # http://www.chilkatsoft.com/receiveUpload.aspx # Therefore, the path part of the URL is: req.put_Path("/receiveUpload.aspx") # Note: You may test uploads to this URL, but anything over 80K will be aborted on the receiving side. # Add some files to the request: # The 1st argument is an arbitrary name. It's the POST form field name. # The 2nd argument is the filename currently existing on # the local filesystem. It may include an absolute or relative # path, or no path at all if it's in the current working directory. success = req.AddFileForUpload("file1","hamlet.xml") if (success != true) print req.lastErrorText() + "\n" exit end success = req.AddFileForUpload("file2","dude.gif") if (success != true) print req.lastErrorText() + "\n" exit end # Send the HTTP POST and get the response. Note: This is a blocking call. # The method does not return until the full HTTP response is received. domain = "www.chilkatsoft.com" port = 80 ssl = false resp = http.SynchronousRequest(domain,port,ssl,req) if (resp == nil ) print http.lastErrorText() + "\n"; else # Display the HTML source of the page returned. print resp.bodyStr() + "\n"; end |
Need a specific example? Send a request to support@chilkatsoft.com
© 2000-2007 Chilkat Software, Inc. All Rights Reserved.