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(Python) Iterate over Direct Child Nodes by IndexDemonstrates some ways to iterate over direct child nodes by index. The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:
<root>
<fruit color="red">apple</fruit>
<fruit color="green">pear</fruit>
<veg color="orange">carrot</veg>
<meat animal="cow">beef</meat>
<xyz>
<fruit color="blue">blueberry</fruit>
<veg color="green">broccoli</veg>
</xyz>
<fruit color="purple">grape</fruit>
<cheese color="yellow">cheddar</cheese>
</root>
import sys import chilkat xml = chilkat.CkXml() # The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml success = xml.LoadXmlFile("get_child.xml") if (success != True): print xml.lastErrorText() sys.exit() # The NumChildren property contains the number of direct # child nodes. Note: The child nodes under "xyz" are NOT # direct children of "root". Therefore, the "root" node has # 7 direct children print "NumChildren = " + str(xml.get_NumChildren()) # Iterate over the direct children by index. The first child # is at index 0. for i in range(0,xml.get_NumChildren()): # access the tag and content directly by index: print str(i) + ": " + xml.getChildTagByIndex(i)\ + " : " + xml.getChildContentByIndex(i) print "-----" # Do the same as the above loop, but get the child node # and access the Tag and Content properties: for i in range(0,xml.get_NumChildren()): # child is a CkXml child = xml.GetChild(i) print str(i) + ": " + child.tag()\ + " : " + child.content() print "-----" # Do the same as the above loop, but instead of creating # a new object instance for each child, call GetChild2 to # update the object's reference instead. for i in range(0,xml.get_NumChildren()): # Navigate to the Nth child. xml.GetChild2(i) print str(i) + ": " + xml.tag() + " : "\ + xml.content() # Navigate back up to the parent: xml.GetParent2() print "-----" # Notice that the Content of the "xyz" node is empty. This is correct. # The "xyz" node has no Content, but 2 direct children. |
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