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(Python) SFTP Simplified Upload

Demonstrates how to upload a file to an SSH server in the simplest way -- by calling UploadFileByName and passing remote and local filepaths.

 Chilkat Python Module Downloads for Windows, Linux, and MAC OS X

import sys
import chilkat

#  Important: It is helpful to send the contents of the
#  sftp.LastErrorText property when requesting support.

sftp = chilkat.CkSFtp()

#  Any string automatically begins a fully-functional 30-day trial.
success = sftp.UnlockComponent("Anything for 30-day trial")
if (success != True):
    print sftp.lastErrorText()
    sys.exit()

#  Set some timeouts, in milliseconds:
sftp.put_ConnectTimeoutMs(15000)
sftp.put_IdleTimeoutMs(15000)

#  Connect to the SSH server.
#  The standard SSH port = 22
#  The hostname may be a hostname or IP address.

hostname = "www.my-ssh-server.com"
port = 22
success = sftp.Connect(hostname,port)
if (success != True):
    print sftp.lastErrorText()
    sys.exit()

#  Authenticate with the SSH server.  Chilkat SFTP supports
#  both password-based authenication as well as public-key
#  authentication.  This example uses password authenication.
success = sftp.AuthenticatePw("myLogin","myPassword")
if (success != True):
    print sftp.lastErrorText()
    sys.exit()

#  After authenticating, the SFTP subsystem must be initialized:
success = sftp.InitializeSftp()
if (success != True):
    print sftp.lastErrorText()
    sys.exit()

#  Upload from the local file to the SSH server.
#  Important -- the remote filepath is the 1st argument,
#  the local filepath is the 2nd argument;
remoteFilePath = "hamlet.xml"
localFilePath = "c:/temp/hamlet.xml"

success = sftp.UploadFileByName(remoteFilePath,localFilePath)
if (success != True):
    print sftp.lastErrorText()
    sys.exit()

print "Success."
 

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