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Upload Files to Web ServerDemonstrates how to upload files from an application to a web server. Note: There must be something provided on the server-side to consume the upload. It could be an ASP or ASP.NET script, Perl, C++ CGI, PHP, Ruby, etc,. However, uploading via HTTP is not the same as uploading via FTP where the FTP server handles receiving the file and saving to disk. The C# code behind http://www.chilkatsoft.com/receiveUpload.aspx may be found at this URL: C# to Receive Upload in ASP.NET.
import sys import chilkat http = chilkat.CkHttp() # Any string unlocks the component for the 1st 30-days. success = http.UnlockComponent("Anything for 30-day trial") if (success != True): print http.lastErrorText() sys.exit() # Build a HTTP request with the files to be uploaded: req = chilkat.CkHttpRequest() req.UseUpload() # The URL we'll be posting to is: # http://www.chilkatsoft.com/receiveUpload.aspx # Therefore, the path part of the URL is: req.put_Path("/receiveUpload.aspx") # Note: You may test uploads to this URL, but anything over 80K will be aborted on the receiving side. # Add some files to the request: # The 1st argument is an arbitrary name. It's the POST form field name. # The 2nd argument is the filename currently existing on # the local filesystem. It may include an absolute or relative # path, or no path at all if it's in the current working directory. success = req.AddFileForUpload("file1","hamlet.xml") if (success != True): print req.lastErrorText() sys.exit() success = req.AddFileForUpload("file2","dude.gif") if (success != True): print req.lastErrorText() sys.exit() # Send the HTTP POST and get the response. Note: This is a blocking call. # The method does not return until the full HTTP response is received. domain = "www.chilkatsoft.com" port = 80 ssl = False resp = http.SynchronousRequest(domain,port,ssl,req) if (resp == None ): print http.lastErrorText() else: # Display the HTML source of the page returned. print resp.bodyStr() |
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