Simple HTTP POST

Demonstrates a simple HTTP POST.

Download Chilkat Python Library

import sys
import chilkat


req = chilkat.CkHttpRequest()
http = chilkat.CkHttp()

#  Any string unlocks the component for the 1st 30-days.
success = http.UnlockComponent("Anything for 30-day trial")
if (success != True):
    print http.lastErrorText()
    sys.exit()

#  This example simulates this FORM:
#  <form action="processPost.asp" method="post">
#  First name: <input type="text" name="firstName"><br />
#  Last name: <input type="text" name="lastName"><br />
#  <input type="submit" value="Submit">
#  </form>
#  The online FORM is found at this URL:
#  http://www.chilkatsoft.com/simpleForm.html

#  Build an HTTP POST Request:
req.UsePost()

#  The FORM target is http://www.chilkatsoft.com/processPost.asp
#  An easy way of filling out most of the HTTP request object
#  is to call SetFromUrl:
req.SetFromUrl("http://www.chilkatsoft.com/processPost.asp")

#  The only remaining task is to add the params to the
#  HTTP request object:
req.AddParam("firstName","Matt")
req.AddParam("lastName","Jones")

#  Send the HTTP POST and get the response.
#  The POST is being sent to chilkatsoft.com, on port 80
#  (the default HTTP port), and not using SSL.

domain = "chilkatsoft.com"
port = 80
ssl = False

#  The HTTP POST is sent here:

resp = http.SynchronousRequest(domain,port,ssl,req)
if (resp == None ):
    print http.lastErrorText()
else:
    #  Display the HTML source of the page returned.
    print resp.bodyStr()