PBKDF2 - Derive Key from Password

Demonstrates how to derive a symmetric encryption key from a password using PBKDF2. This example matches the results found at this URL: http://www.di-mgt.com.au/cryptoKDFs.html#examplespbkdf

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// Needs #include <CkCrypt2.h>

    CkString strOut;

    CkCrypt2 crypt;

    bool success;
    success = crypt.UnlockComponent("Anything for 30-day trial");
    if (success != true) {
        strOut.append(crypt.lastErrorText());
        strOut.append("\r\n");
        SetDlgItemText(IDC_EDIT1,strOut.getUnicode());
        return;
    }

    const char * hexKey;
    //  http://www.di-mgt.com.au/cryptoKDFs.html#examplespbkdf

    const char * pw;
    pw = "password";
    const char * pwCharset;
    pwCharset = "ansi";
    //  Hash algorithms may be: sha1, md2, md5, etc.
    const char * hashAlg;
    hashAlg = "sha1";
    //  The salt should be 8 bytes:
    const char * saltHex;
    saltHex = "78578E5A5D63CB06";
    long iterationCount;
    iterationCount = 2048;
    //  Derive a 192-bit key from the password.
    long outputBitLen;
    outputBitLen = 192;

    //  The derived key is returned as a hex or base64 encoded string.
    //  (Note: The salt argument must be a string that also uses
    //  the same encoding.)
    const char * enc;
    enc = "hex";

    hexKey = crypt.pbkdf2(pw,pwCharset,hashAlg,saltHex,iterationCount,outputBitLen,enc);

    strOut.append(hexKey);
    strOut.append("\r\n");

    //  The output should have this value:
    //  BFDE6BE94DF7E11DD409BCE20A0255EC327CB936FFE93643



    SetDlgItemText(IDC_EDIT1,strOut.getUnicode());