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(Java) XML Sort Records by ContentDemonstrates the SortRecordsByContent method. The input XML, available at http://www.chilkatsoft.com/data/fruitRecordsSort.xml, is this:
<root>
<fruits>
<fruit>
<name>apple</name>
<color>red</color>
</fruit>
<fruit>
<name>banana</name>
<color>yellow</color>
</fruit>
<fruit>
<name>blackberry</name>
<color>purple</color>
</fruit>
<fruit>
<name>blueberry</name>
<color>blue</color>
</fruit>
<fruit>
<name>orange</name>
<color>orange</color>
</fruit>
<fruit>
<name>pear</name>
<color>green</color>
</fruit>
</fruits>
</root>
import com.chilkatsoft.*;
public class ChilkatExample {
static {
try {
System.loadLibrary("chilkat");
} catch (UnsatisfiedLinkError e) {
System.err.println("Native code library failed to load.\n" + e);
System.exit(1);
}
}
public static void main(String argv[])
{
CkXml xml = new CkXml();
CkXml xSortRoot;
boolean success;
// The sample input XML is available at http://www.chilkatsoft.com/data/fruitRecordsSort.xml
success = xml.LoadXmlFile("fruitRecordsSort.xml");
if (success != true) {
System.out.println(xml.lastErrorText());
return;
}
// The "fruit" records are direct children of the "fruits" node.
// Therefore, to sort the fruit records, the SortRecordsByContent
// method must be called from the "fruits" node.
xSortRoot = xml.FindChild("fruits");
// Sort by the "name" field in ascending order.
boolean bAscending;
bAscending = true;
xSortRoot.SortRecordsByContent("name",bAscending);
// Show the result:
System.out.println(xml.getXml());
//
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