Chilkat HOME ASP Visual Basic VB.NET C# Visual C++ C MFC Delphi FoxPro Java Perl PHP Python Ruby SQL Server VBScript
|
XMLHTTP / XMLHttpRequestShows how to send an XMLHttpRequest POST and get the response. The body of the HTTP request is an XML document. LOCAL loReq LOCAL loHttp LOCAL lnSuccess LOCAL lcDomain LOCAL lnPort LOCAL lnSsl LOCAL loResp loReq = CreateObject('Chilkat.HttpRequest') loHttp = CreateObject('Chilkat.Http') * Any string unlocks the component for the 1st 30-days. lnSuccess = loHttp.UnlockComponent("Anything for 30-day trial") IF (lnSuccess <> 1) THEN =MESSAGEBOX(loHttp.LastErrorText) QUIT ENDIF * Note: You must first replace the domain and path of this example with real values. * There is nothing at http://www.chilkatsoft.com/something.asp * Build an XMLHTTP request. The XML passed to UseXmlHttp is sent * in the body of the request. loReq.UseXmlHttp("<test>This is the XML to be sent</test>") loReq.Path = "/something.asp" * Send the HTTP POST and get the response. Note: This is a blocking call. * The method does not return until the full HTTP response is received. lcDomain = "www.chilkatsoft.com" lnPort = 80 lnSsl = 0 loResp = loHttp.SynchronousRequest(lcDomain,lnPort,lnSsl,loReq) IF (loResp = NULL ) THEN ? loHttp.LastErrorText ELSE * Display the body of the response. ? loResp.BodyStr ENDIF |
Need a specific example? Send a request to support@chilkatsoft.com
© 2000-2010 Chilkat Software, Inc. All Rights Reserved.
Mail Component · .NET Email Component · ASP Mail Component · XML Parser