(Visual FoxPro) Send XMLHttpRequest using PUT, GET, DELETE, or any HTTP Request Method

The PostXml method is the easiest way to send an XMLHttpRequest using the POST HTTP verb (which is by far the most common). To use a different HTTP request method (such as PUT, GET, DELETE, etc.), the SynchronousRequest method should be called. It provides more flexibility in constructing the exact HTTP request desired.

Download Chilkat HTTP ActiveX

LOCAL loHttp
LOCAL lnSuccess
LOCAL lcXmlStr
LOCAL lcEndpointDomain
LOCAL lnEndpointPort
LOCAL lnEndpointSsl
LOCAL loRequest
LOCAL loResponse

loHttp = CreateObject('Chilkat.Http')

*  Any string unlocks the component for the 1st 30-days.
lnSuccess = loHttp.UnlockComponent("Anything for 30-day trial")
IF (lnSuccess <> 1) THEN
    ? loHttp.LastErrorText
    QUIT
ENDIF

*  The XML sent in the body of the request is application
*  specified -- it should contain whatever the server-side
*  application is expecting..

lcXmlStr = [<?xml version="1.0" encoding="UTF-8"?><appXml><something>123</something></appXml>]

*  If the service endpoint is  "http://www.chilkatsoft.com/xmlEcho.asp",
*  then we have the following arguments to be passed to
*  SynchronousRequest:

lcEndpointDomain = "www.chilkatsoft.com"

lnEndpointPort = 80

lnEndpointSsl = 0

*  Prepare the HTTP request object:
loRequest = CreateObject('Chilkat.HttpRequest')
loRequest.Path = "/xmlEcho.asp"

*  This example will use the "PUT" HTTP request method
*  (also known as HTTP verb)
loRequest.HttpVerb = "PUT"
loRequest.ContentType = "text/xml"
loRequest.Charset = "utf-8"
loRequest.LoadBodyFromString(lcXmlStr,"utf-8")

loResponse = loHttp.SynchronousRequest(lcEndpointDomain,lnEndpointPort,lnEndpointSsl,loRequest)
IF (loResponse = NULL ) THEN
    ? loHttp.LastErrorText
    QUIT
ENDIF

*  The raw HTTP request sent by the above call is:
*  
PUT /xmlEcho.asp HTTP/1.1
Content-Type: text/xml
Host: www.chilkatsoft.com
Content-Length: 81

<?xml version="1.0" encoding="UTF-8"?><appXml><something>123</something></appXml>


*  Examine the Body of the HTTP response
*  This would be the XML response sent by the server.
? loResponse.BodyStr

RELEASE loResponse