How to Examine the HTTP Header + Body for a POST to be sent

This example shows how to use GenerateRequestText to get the HTTP request (headers + body) that would be sent if SynchronousRequest was called with the HTTP request object.

Important: The hostnames and paths in this examples are not intended to be real examples. You should replace all hostnames, paths, etc. with valid data for your own Web service.

Download Chilkat HTTP ActiveX

LOCAL loReq
LOCAL loHttp
LOCAL lnSuccess
LOCAL lcRequestText
LOCAL loResp

loReq = CreateObject('Chilkat.HttpRequest')
loHttp = CreateObject('Chilkat.Http')

*  Any string unlocks the component for the 1st 30-days.
lnSuccess = loHttp.UnlockComponent("30-day trial")
IF (lnSuccess <> 1) THEN
    =MESSAGEBOX(loHttp.LastErrorText)
    QUIT
ENDIF

*  Build an XMLHTTP request.  The XML passed to UseXmlHttp is sent
*  in the body of the request.
loReq.UseXmlHttp("<test>This is the XML to be sent</test>")
loReq.Path = "/protus/xmlwebservices/xmlsubmitter/messaging.asmx"

*  Add a custom header:
loReq.AddHeader("SOAPAction","https://www.notarealdomain.com/WebServices/Messaging/2005/2/SendSingleFax")

lcRequestText = loReq.GenerateRequestText()

? lcRequestText
? "----------------------"

*  Send the HTTP POST and get the response.  Note: This is a blocking call.
*  The method does not return until the full HTTP response is received.

loResp = loHttp.SynchronousRequest("www.notarealdomain.com",443,1,loReq)
IF (loResp = NULL ) THEN
    ? loHttp.LastErrorText
ELSE
    *  Display the body of the response.
    ? loResp.BodyStr
ENDIF