(C#) Iterate over Direct Child Nodes by Index

Demonstrates some ways to iterate over direct child nodes by index.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Download: Chilkat .NET Assemblies

Chilkat.Xml xml = new Chilkat.Xml();
Chilkat.Xml child = null;

bool success;
//  The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
success = xml.LoadXmlFile("get_child.xml");
if (success != true) {
    textBox1.Text += xml.LastErrorText + "\r\n";
    return;
}

//  The NumChildren property contains the number of direct
//  child nodes.  Note: The child nodes under "xyz" are NOT
//  direct children of "root".  Therefore, the "root" node has
//  7 direct children
textBox1.Text += "NumChildren = " + xml.NumChildren + "\r\n";

//  Iterate over the direct children by index. The first child
//  is at index 0.
int i;
for (i = 0; i <= xml.NumChildren - 1; i++) {
    //   access the tag and content directly by index:
    textBox1.Text += Convert.ToString(i) + ": "
         + xml.GetChildTagByIndex(i) + " : " + xml.GetChildContentByIndex(i) + "\r\n";

}

textBox1.Text += "-----" + "\r\n";

//  Do the same as the above loop, but get the child node
//  and access the Tag and Content properties:
for (i = 0; i <= xml.NumChildren - 1; i++) {
    child = xml.GetChild(i);
    textBox1.Text += Convert.ToString(i) + ": "
         + child.Tag + " : " + child.Content + "\r\n";

}

textBox1.Text += "-----" + "\r\n";

//  Do the same as the above loop, but instead of creating
//  a new object instance for each child, call GetChild2 to
//  update the object's reference instead.
for (i = 0; i <= xml.NumChildren - 1; i++) {
    //  Navigate to the Nth child.
    xml.GetChild2(i);
    textBox1.Text += Convert.ToString(i) + ": "
         + xml.Tag + " : " + xml.Content + "\r\n";
    //  Navigate back up to the parent:
    xml.GetParent2();
}

textBox1.Text += "-----" + "\r\n";

//  Notice that the Content of the "xyz" node is empty.  This is correct.
//  The "xyz" node has no Content, but 2 direct children.