(C#) Send XMLHttpRequest and Get Response

Demonstrates how to send an HTTP XML request and retrieve the response.

Download: Chilkat .NET Assemblies

Chilkat.Http http = new Chilkat.Http();

bool success;

//  Any string unlocks the component for the 1st 30-days.
success = http.UnlockComponent("Anything for 30-day trial");
if (success != true) {
    textBox1.Text += http.LastErrorText + "\r\n";
    return;
}

//  The XML sent in the body of the request is application
//  specified -- it should contain whatever the server-side
//  application is expecting..
string xmlStr;
xmlStr = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><appXml><something>123</something></appXml>";

//  The PostXml method may be called to send the XMLHttpRequest
//  using the "POST" HTTP method (also known as "verb").
string urlEndpoint;
urlEndpoint = "http://www.chilkatsoft.com/xmlEcho.asp";
string xmlCharset;
xmlCharset = "utf-8";

Chilkat.HttpResponse response = null;
response = http.PostXml(urlEndpoint,xmlStr,xmlCharset);
if (response == null ) {
    textBox1.Text += http.LastErrorText + "\r\n";
    return;
}

//  The raw HTTP request sent by the above call is:
//  
POST /xmlEcho.asp HTTP/1.1
Content-Type: text/xml
User-Agent: Chilkat/1.0.0 (+http://www.chilkatsoft.com/ChilkatHttpUA.asp)
Host: www.chilkatsoft.com
Accept: */*
Accept-Charset: ISO-8859-1,utf-8;q=0.7,*; q=0.7
Accept-Language: en-us,en;q=0.5
Accept-Encoding: gzip
Content-Length: 81

<?xml version="1.0" encoding="UTF-8"?><appXml><something>123</something></appXml>


//  Examine the Body of the HTTP response
//  This would be the XML response sent by the server.
textBox1.Text += response.BodyStr + "\r\n";