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(ASP) XML Sort Records by ContentDemonstrates the SortRecordsByContent method. The input XML, available at http://www.chilkatsoft.com/data/fruitRecordsSort.xml, is this:
<root>
<fruits>
<fruit>
<name>apple</name>
<color>red</color>
</fruit>
<fruit>
<name>banana</name>
<color>yellow</color>
</fruit>
<fruit>
<name>blackberry</name>
<color>purple</color>
</fruit>
<fruit>
<name>blueberry</name>
<color>blue</color>
</fruit>
<fruit>
<name>orange</name>
<color>orange</color>
</fruit>
<fruit>
<name>pear</name>
<color>green</color>
</fruit>
</fruits>
</root>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<%
set xml = Server.CreateObject("Chilkat.Xml")
' The sample input XML is available at http://www.chilkatsoft.com/data/fruitRecordsSort.xml
success = xml.LoadXmlFile("fruitRecordsSort.xml")
If (success <> 1) Then
Response.Write "<pre>" & Server.HTMLEncode( xml.LastErrorText) & "</pre>"
End If
' The "fruit" records are direct children of the "fruits" node.
' Therefore, to sort the fruit records, the SortRecordsByContent
' method must be called from the "fruits" node.
' xSortRoot is a Chilkat.Xml
Set xSortRoot = xml.FindChild("fruits")
' Sort by the "name" field in ascending order.
bAscending = 1
xSortRoot.SortRecordsByContent "name",bAscending
' Show the result:
Response.Write "<pre>" & Server.HTMLEncode( xml.GetXml()) & "</pre>"
'
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