(ASP) Iterate over Direct Child Nodes by Index

Demonstrates some ways to iterate over direct child nodes by index.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Download Chilkat XML ActiveX

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<%
set xml = Server.CreateObject("Chilkat.Xml")

'  The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
success = xml.LoadXmlFile("get_child.xml")
If (success <> 1) Then
    Response.Write "<pre>" & Server.HTMLEncode( xml.LastErrorText) & "</pre>"

End If

'  The NumChildren property contains the number of direct
'  child nodes.  Note: The child nodes under "xyz" are NOT
'  direct children of "root".  Therefore, the "root" node has
'  7 direct children
Response.Write "<pre>" & Server.HTMLEncode( "NumChildren = " _
     & xml.NumChildren) & "</pre>"

'  Iterate over the direct children by index. The first child
'  is at index 0.

For i = 0 To xml.NumChildren - 1
    '   access the tag and content directly by index:
    Response.Write "<pre>" & Server.HTMLEncode( i _
         & ": " & xml.GetChildTagByIndex(i) & " : " _
         & xml.GetChildContentByIndex(i)) & "</pre>"

Next
Response.Write "<pre>" & Server.HTMLEncode( "-----") & "</pre>"

'  Do the same as the above loop, but get the child node
'  and access the Tag and Content properties:
For i = 0 To xml.NumChildren - 1
    ' child is a Chilkat.Xml
    Set child = xml.GetChild(i)
    Response.Write "<pre>" & Server.HTMLEncode( i _
         & ": " & child.Tag & " : " & child.Content) & "</pre>"

Next
Response.Write "<pre>" & Server.HTMLEncode( "-----") & "</pre>"

'  Do the same as the above loop, but instead of creating
'  a new object instance for each child, call GetChild2 to
'  update the object's reference instead.
For i = 0 To xml.NumChildren - 1
    '  Navigate to the Nth child.
    xml.GetChild2 i
    Response.Write "<pre>" & Server.HTMLEncode( i _
         & ": " & xml.Tag & " : " & xml.Content) & "</pre>"
    '  Navigate back up to the parent:
    xml.GetParent2 
Next
Response.Write "<pre>" & Server.HTMLEncode( "-----") & "</pre>"

'  Notice that the Content of the "xyz" node is empty.  This is correct.
'  The "xyz" node has no Content, but 2 direct children.

%>
</body>
</html>