Simple HTTP POST

Demonstrates a simple HTTP POST.

Download Chilkat HTTP ActiveX

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<%

set req = Server.CreateObject("Chilkat.HttpRequest")
set http = Server.CreateObject("Chilkat.Http")

'  Any string unlocks the component for the 1st 30-days.
success = http.UnlockComponent("Anything for 30-day trial")
If (success <> 1) Then
    Response.Write http.LastErrorText & "<br>"

End If

'  This example simulates this FORM:
'  <form action="processPost.asp" method="post">
'  First name: <input type="text" name="firstName"><br />
'  Last name: <input type="text" name="lastName"><br />
'  <input type="submit" value="Submit">
'  </form>
'  The online FORM is found at this URL:
'  http://www.chilkatsoft.com/simpleForm.html

'  Build an HTTP POST Request:
req.UsePost 

'  The FORM target is http://www.chilkatsoft.com/processPost.asp
'  An easy way of filling out most of the HTTP request object
'  is to call SetFromUrl:
req.SetFromUrl "http://www.chilkatsoft.com/processPost.asp"

'  The only remaining task is to add the params to the
'  HTTP request object:
req.AddParam "firstName","Matt"
req.AddParam "lastName","Jones"

'  Send the HTTP POST and get the response.
'  The POST is being sent to chilkatsoft.com, on port 80
'  (the default HTTP port), and not using SSL.

domain = "chilkatsoft.com"
port = 80
ssl = 0

'  The HTTP POST is sent here:

Set resp = http.SynchronousRequest(domain,port,ssl,req)
If (resp Is Nothing ) Then
    Response.Write Server.HTMLEncode( http.LastErrorText) & "<br>"
Else
    '  Display the HTML source of the page returned.
    Response.Write Server.HTMLEncode( resp.BodyStr) & "<br>"

End If

%>
</body>
</html>

Need a specific example? Send a request to support@chilkatsoft.com