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PBKDF2 - Derive Key from PasswordDemonstrates how to derive a symmetric encryption key from a password using PBKDF2. This example matches the results found at this URL: http://www.di-mgt.com.au/cryptoKDFs.html#examplespbkdf
<html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> </head> <body> <% set crypt = Server.CreateObject("Chilkat.Crypt2") success = crypt.UnlockComponent("Anything for 30-day trial") If (success <> 1) Then Response.Write "<pre>" & Server.HTMLEncode(crypt.LastErrorText) & "</pre>" End If ' http://www.di-mgt.com.au/cryptoKDFs.html#examplespbkdf pw = "password" pwCharset = "ansi" ' Hash algorithms may be: sha1, md2, md5, etc. hashAlg = "sha1" ' The salt should be 8 bytes: saltHex = "78578E5A5D63CB06" iterationCount = 2048 ' Derive a 192-bit key from the password. outputBitLen = 192 ' The derived key is returned as a hex or base64 encoded string. ' (Note: The salt argument must be a string that also uses ' the same encoding.) enc = "hex" hexKey = crypt.Pbkdf2(pw,pwCharset,hashAlg,saltHex,iterationCount,outputBitLen,enc) Response.Write "<pre>" & Server.HTMLEncode( hexKey) & "</pre>" ' The output should have this value: ' BFDE6BE94DF7E11DD409BCE20A0255EC327CB936FFE93643 %> </body> </html> |
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